3(c-2)=22(c-6)

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Solution for 3(c-2)=22(c-6) equation: 



3(c-2)=22(c-6)

We move all terms to the left:

3(c-2)-(22(c-6))=0

We multiply parentheses

3c-(22(c-6))-6=0



We calculate terms in parentheses: -(22(c-6)), so:

22(c-6)

We multiply parentheses

22c-132

Back to the equation:

-(22c-132)



We get rid of parentheses

3c-22c+132-6=0

We add all the numbers together, and all the variables

-19c+126=0

We move all terms containing c to the left, all other terms to the right

-19c=-126

c=-126/-19

c=6+12/19

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