3(c-2)=4(c+1)

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Solution for 3(c-2)=4(c+1) equation:


Simplifying
3(c + -2) = 4(c + 1)

Reorder the terms:
3(-2 + c) = 4(c + 1)
(-2 * 3 + c * 3) = 4(c + 1)
(-6 + 3c) = 4(c + 1)

Reorder the terms:
-6 + 3c = 4(1 + c)
-6 + 3c = (1 * 4 + c * 4)
-6 + 3c = (4 + 4c)

Solving
-6 + 3c = 4 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-6 + 3c + -4c = 4 + 4c + -4c

Combine like terms: 3c + -4c = -1c
-6 + -1c = 4 + 4c + -4c

Combine like terms: 4c + -4c = 0
-6 + -1c = 4 + 0
-6 + -1c = 4

Add '6' to each side of the equation.
-6 + 6 + -1c = 4 + 6

Combine like terms: -6 + 6 = 0
0 + -1c = 4 + 6
-1c = 4 + 6

Combine like terms: 4 + 6 = 10
-1c = 10

Divide each side by '-1'.
c = -10

Simplifying
c = -10

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