3(c-2)=4(c+5)

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Solution for 3(c-2)=4(c+5) equation: 



3(c-2)=4(c+5)

We move all terms to the left:

3(c-2)-(4(c+5))=0

We multiply parentheses

3c-(4(c+5))-6=0



We calculate terms in parentheses: -(4(c+5)), so:

4(c+5)

We multiply parentheses

4c+20

Back to the equation:

-(4c+20)



We get rid of parentheses

3c-4c-20-6=0

We add all the numbers together, and all the variables

-1c-26=0

We move all terms containing c to the left, all other terms to the right

-c=26

c=26/-1

c=-26

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