3(c-3)+20c=60

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Solution for 3(c-3)+20c=60 equation: 



3(c-3)+20c=60

We move all terms to the left:

3(c-3)+20c-(60)=0

We add all the numbers together, and all the variables

20c+3(c-3)-60=0

We multiply parentheses

20c+3c-9-60=0

We add all the numbers together, and all the variables

23c-69=0

We move all terms containing c to the left, all other terms to the right

23c=69

c=69/23

c=3

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