3(c-4)+2c=8-5(4-c)

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Solution for 3(c-4)+2c=8-5(4-c) equation: 


Simplifying
3(c + -4) + 2c = 8 + -5(4 + -1c)

Reorder the terms:
3(-4 + c) + 2c = 8 + -5(4 + -1c)
(-4 * 3 + c * 3) + 2c = 8 + -5(4 + -1c)
(-12 + 3c) + 2c = 8 + -5(4 + -1c)

Combine like terms: 3c + 2c = 5c
-12 + 5c = 8 + -5(4 + -1c)
-12 + 5c = 8 + (4 * -5 + -1c * -5)
-12 + 5c = 8 + (-20 + 5c)

Combine like terms: 8 + -20 = -12
-12 + 5c = -12 + 5c

Add '12' to each side of the equation.
-12 + 12 + 5c = -12 + 12 + 5c

Combine like terms: -12 + 12 = 0
0 + 5c = -12 + 12 + 5c
5c = -12 + 12 + 5c

Combine like terms: -12 + 12 = 0
5c = 0 + 5c
5c = 5c

Add '-5c' to each side of the equation.
5c + -5c = 5c + -5c

Combine like terms: 5c + -5c = 0
0 = 5c + -5c

Combine like terms: 5c + -5c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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