3(c-4)+5=4+c-11

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Solution for 3(c-4)+5=4+c-11 equation: 


Simplifying
3(c + -4) + 5 = 4 + c + -11

Reorder the terms:
3(-4 + c) + 5 = 4 + c + -11
(-4 * 3 + c * 3) + 5 = 4 + c + -11
(-12 + 3c) + 5 = 4 + c + -11

Reorder the terms:
-12 + 5 + 3c = 4 + c + -11

Combine like terms: -12 + 5 = -7
-7 + 3c = 4 + c + -11

Reorder the terms:
-7 + 3c = 4 + -11 + c

Combine like terms: 4 + -11 = -7
-7 + 3c = -7 + c

Add '7' to each side of the equation.
-7 + 7 + 3c = -7 + 7 + c

Combine like terms: -7 + 7 = 0
0 + 3c = -7 + 7 + c
3c = -7 + 7 + c

Combine like terms: -7 + 7 = 0
3c = 0 + c
3c = c

Solving
3c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
3c + -1c = c + -1c

Combine like terms: 3c + -1c = 2c
2c = c + -1c

Combine like terms: c + -1c = 0
2c = 0

Divide each side by '2'.
c = 0

Simplifying
c = 0

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