3(c-4)+6=42

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Solution for 3(c-4)+6=42 equation: 



3(c-4)+6=42

We move all terms to the left:

3(c-4)+6-(42)=0

We add all the numbers together, and all the variables

3(c-4)-36=0

We multiply parentheses

3c-12-36=0

We add all the numbers together, and all the variables

3c-48=0

We move all terms containing c to the left, all other terms to the right

3c=48

c=48/3

c=16

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