3(c-4)+8=2(2c+1)-9

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Solution for 3(c-4)+8=2(2c+1)-9 equation: 



3(c-4)+8=2(2c+1)-9

We move all terms to the left:

3(c-4)+8-(2(2c+1)-9)=0

We multiply parentheses

3c-(2(2c+1)-9)-12+8=0



We calculate terms in parentheses: -(2(2c+1)-9), so:

2(2c+1)-9

We multiply parentheses

4c+2-9

We add all the numbers together, and all the variables

4c-7

Back to the equation:

-(4c-7)



We add all the numbers together, and all the variables

3c-(4c-7)-4=0

We get rid of parentheses

3c-4c+7-4=0

We add all the numbers together, and all the variables

-1c+3=0

We move all terms containing c to the left, all other terms to the right

-c=-3

c=-3/-1

c=+3

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