3(c-4)+8=2+c-6

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Solution for 3(c-4)+8=2+c-6 equation: 


Simplifying
3(c + -4) + 8 = 2 + c + -6

Reorder the terms:
3(-4 + c) + 8 = 2 + c + -6
(-4 * 3 + c * 3) + 8 = 2 + c + -6
(-12 + 3c) + 8 = 2 + c + -6

Reorder the terms:
-12 + 8 + 3c = 2 + c + -6

Combine like terms: -12 + 8 = -4
-4 + 3c = 2 + c + -6

Reorder the terms:
-4 + 3c = 2 + -6 + c

Combine like terms: 2 + -6 = -4
-4 + 3c = -4 + c

Add '4' to each side of the equation.
-4 + 4 + 3c = -4 + 4 + c

Combine like terms: -4 + 4 = 0
0 + 3c = -4 + 4 + c
3c = -4 + 4 + c

Combine like terms: -4 + 4 = 0
3c = 0 + c
3c = c

Solving
3c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
3c + -1c = c + -1c

Combine like terms: 3c + -1c = 2c
2c = c + -1c

Combine like terms: c + -1c = 0
2c = 0

Divide each side by '2'.
c = 0

Simplifying
c = 0

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