3(c-4)-2c-8=9(c+2)+1

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Solution for 3(c-4)-2c-8=9(c+2)+1 equation: 



3(c-4)-2c-8=9(c+2)+1

We move all terms to the left:

3(c-4)-2c-8-(9(c+2)+1)=0

We add all the numbers together, and all the variables

-2c+3(c-4)-(9(c+2)+1)-8=0

We multiply parentheses

-2c+3c-(9(c+2)+1)-12-8=0



We calculate terms in parentheses: -(9(c+2)+1), so:

9(c+2)+1

We multiply parentheses

9c+18+1

We add all the numbers together, and all the variables

9c+19

Back to the equation:

-(9c+19)



We add all the numbers together, and all the variables

c-(9c+19)-20=0

We get rid of parentheses

c-9c-19-20=0

We add all the numbers together, and all the variables

-8c-39=0

We move all terms containing c to the left, all other terms to the right

-8c=39

c=39/-8

c=-4+7/8

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