3(c-4)=(-9)=21

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Solution for 3(c-4)=(-9)=21 equation: 



3(c-4)=(-9)=21

We move all terms to the left:

3(c-4)-((-9))=0

We add all the numbers together, and all the variables

3(c-4)+9=0

We multiply parentheses

3c-12+9=0

We add all the numbers together, and all the variables

3c-3=0

We move all terms containing c to the left, all other terms to the right

3c=3

c=3/3

c=1

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