3(c-4)=3c-12

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Solution for 3(c-4)=3c-12 equation:


Simplifying
3(c + -4) = 3c + -12

Reorder the terms:
3(-4 + c) = 3c + -12
(-4 * 3 + c * 3) = 3c + -12
(-12 + 3c) = 3c + -12

Reorder the terms:
-12 + 3c = -12 + 3c

Add '12' to each side of the equation.
-12 + 12 + 3c = -12 + 12 + 3c

Combine like terms: -12 + 12 = 0
0 + 3c = -12 + 12 + 3c
3c = -12 + 12 + 3c

Combine like terms: -12 + 12 = 0
3c = 0 + 3c
3c = 3c

Add '-3c' to each side of the equation.
3c + -3c = 3c + -3c

Combine like terms: 3c + -3c = 0
0 = 3c + -3c

Combine like terms: 3c + -3c = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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