3(c-4)=8(c-9)

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Solution for 3(c-4)=8(c-9) equation: 



3(c-4)=8(c-9)

We move all terms to the left:

3(c-4)-(8(c-9))=0

We multiply parentheses

3c-(8(c-9))-12=0



We calculate terms in parentheses: -(8(c-9)), so:

8(c-9)

We multiply parentheses

8c-72

Back to the equation:

-(8c-72)



We get rid of parentheses

3c-8c+72-12=0

We add all the numbers together, and all the variables

-5c+60=0

We move all terms containing c to the left, all other terms to the right

-5c=-60

c=-60/-5

c=+12

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