3(c-5)+3=2+c-14

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Solution for 3(c-5)+3=2+c-14 equation: 


Simplifying
3(c + -5) + 3 = 2 + c + -14

Reorder the terms:
3(-5 + c) + 3 = 2 + c + -14
(-5 * 3 + c * 3) + 3 = 2 + c + -14
(-15 + 3c) + 3 = 2 + c + -14

Reorder the terms:
-15 + 3 + 3c = 2 + c + -14

Combine like terms: -15 + 3 = -12
-12 + 3c = 2 + c + -14

Reorder the terms:
-12 + 3c = 2 + -14 + c

Combine like terms: 2 + -14 = -12
-12 + 3c = -12 + c

Add '12' to each side of the equation.
-12 + 12 + 3c = -12 + 12 + c

Combine like terms: -12 + 12 = 0
0 + 3c = -12 + 12 + c
3c = -12 + 12 + c

Combine like terms: -12 + 12 = 0
3c = 0 + c
3c = c

Solving
3c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
3c + -1c = c + -1c

Combine like terms: 3c + -1c = 2c
2c = c + -1c

Combine like terms: c + -1c = 0
2c = 0

Divide each side by '2'.
c = 0

Simplifying
c = 0

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