3(c-5)+5=2+c-12

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Solution for 3(c-5)+5=2+c-12 equation: 


Simplifying
3(c + -5) + 5 = 2 + c + -12

Reorder the terms:
3(-5 + c) + 5 = 2 + c + -12
(-5 * 3 + c * 3) + 5 = 2 + c + -12
(-15 + 3c) + 5 = 2 + c + -12

Reorder the terms:
-15 + 5 + 3c = 2 + c + -12

Combine like terms: -15 + 5 = -10
-10 + 3c = 2 + c + -12

Reorder the terms:
-10 + 3c = 2 + -12 + c

Combine like terms: 2 + -12 = -10
-10 + 3c = -10 + c

Add '10' to each side of the equation.
-10 + 10 + 3c = -10 + 10 + c

Combine like terms: -10 + 10 = 0
0 + 3c = -10 + 10 + c
3c = -10 + 10 + c

Combine like terms: -10 + 10 = 0
3c = 0 + c
3c = c

Solving
3c = c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1c' to each side of the equation.
3c + -1c = c + -1c

Combine like terms: 3c + -1c = 2c
2c = c + -1c

Combine like terms: c + -1c = 0
2c = 0

Divide each side by '2'.
c = 0

Simplifying
c = 0

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