3(c-5)=-4c-43

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Solution for 3(c-5)=-4c-43 equation: 



3(c-5)=-4c-43

We move all terms to the left:

3(c-5)-(-4c-43)=0

We multiply parentheses

3c-(-4c-43)-15=0

We get rid of parentheses

3c+4c+43-15=0

We add all the numbers together, and all the variables

7c+28=0

We move all terms containing c to the left, all other terms to the right

7c=-28

c=-28/7

c=-4

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