3(c-5)=12

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Solution for 3(c-5)=12 equation: 



3(c-5)=12

We move all terms to the left:

3(c-5)-(12)=0

We multiply parentheses

3c-15-12=0

We add all the numbers together, and all the variables

3c-27=0

We move all terms containing c to the left, all other terms to the right

3c=27

c=27/3

c=9

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