3(c-5)=2(c-2)

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Solution for 3(c-5)=2(c-2) equation: 


Simplifying
3(c + -5) = 2(c + -2)

Reorder the terms:
3(-5 + c) = 2(c + -2)
(-5 * 3 + c * 3) = 2(c + -2)
(-15 + 3c) = 2(c + -2)

Reorder the terms:
-15 + 3c = 2(-2 + c)
-15 + 3c = (-2 * 2 + c * 2)
-15 + 3c = (-4 + 2c)

Solving
-15 + 3c = -4 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
-15 + 3c + -2c = -4 + 2c + -2c

Combine like terms: 3c + -2c = 1c
-15 + 1c = -4 + 2c + -2c

Combine like terms: 2c + -2c = 0
-15 + 1c = -4 + 0
-15 + 1c = -4

Add '15' to each side of the equation.
-15 + 15 + 1c = -4 + 15

Combine like terms: -15 + 15 = 0
0 + 1c = -4 + 15
1c = -4 + 15

Combine like terms: -4 + 15 = 11
1c = 11

Divide each side by '1'.
c = 11

Simplifying
c = 11

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