3(c-5)=4(c-7)

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Solution for 3(c-5)=4(c-7) equation: 


Simplifying
3(c + -5) = 4(c + -7)

Reorder the terms:
3(-5 + c) = 4(c + -7)
(-5 * 3 + c * 3) = 4(c + -7)
(-15 + 3c) = 4(c + -7)

Reorder the terms:
-15 + 3c = 4(-7 + c)
-15 + 3c = (-7 * 4 + c * 4)
-15 + 3c = (-28 + 4c)

Solving
-15 + 3c = -28 + 4c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-4c' to each side of the equation.
-15 + 3c + -4c = -28 + 4c + -4c

Combine like terms: 3c + -4c = -1c
-15 + -1c = -28 + 4c + -4c

Combine like terms: 4c + -4c = 0
-15 + -1c = -28 + 0
-15 + -1c = -28

Add '15' to each side of the equation.
-15 + 15 + -1c = -28 + 15

Combine like terms: -15 + 15 = 0
0 + -1c = -28 + 15
-1c = -28 + 15

Combine like terms: -28 + 15 = -13
-1c = -13

Divide each side by '-1'.
c = 13

Simplifying
c = 13

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