3(c-5)=6(c+3)

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Solution for 3(c-5)=6(c+3) equation: 



3(c-5)=6(c+3)

We move all terms to the left:

3(c-5)-(6(c+3))=0

We multiply parentheses

3c-(6(c+3))-15=0



We calculate terms in parentheses: -(6(c+3)), so:

6(c+3)

We multiply parentheses

6c+18

Back to the equation:

-(6c+18)



We get rid of parentheses

3c-6c-18-15=0

We add all the numbers together, and all the variables

-3c-33=0

We move all terms containing c to the left, all other terms to the right

-3c=33

c=33/-3

c=-11

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