3(c-5)=7c+12

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Solution for 3(c-5)=7c+12 equation: 



3(c-5)=7c+12

We move all terms to the left:

3(c-5)-(7c+12)=0

We multiply parentheses

3c-(7c+12)-15=0

We get rid of parentheses

3c-7c-12-15=0

We add all the numbers together, and all the variables

-4c-27=0

We move all terms containing c to the left, all other terms to the right

-4c=27

c=27/-4

c=-6+3/4

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