3(c-5)=7c+c

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Solution for 3(c-5)=7c+c equation: 



3(c-5)=7c+c

We move all terms to the left:

3(c-5)-(7c+c)=0

We add all the numbers together, and all the variables

3(c-5)-(+8c)=0

We multiply parentheses

3c-(+8c)-15=0

We get rid of parentheses

3c-8c-15=0

We add all the numbers together, and all the variables

-5c-15=0

We move all terms containing c to the left, all other terms to the right

-5c=15

c=15/-5

c=-3

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