3(cq-5)=2(q+5)

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Solution for 3(cq-5)=2(q+5) equation:


Simplifying
3(cq + -5) = 2(q + 5)

Reorder the terms:
3(-5 + cq) = 2(q + 5)
(-5 * 3 + cq * 3) = 2(q + 5)
(-15 + 3cq) = 2(q + 5)

Reorder the terms:
-15 + 3cq = 2(5 + q)
-15 + 3cq = (5 * 2 + q * 2)
-15 + 3cq = (10 + 2q)

Solving
-15 + 3cq = 10 + 2q

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '15' to each side of the equation.
-15 + 15 + 3cq = 10 + 15 + 2q

Combine like terms: -15 + 15 = 0
0 + 3cq = 10 + 15 + 2q
3cq = 10 + 15 + 2q

Combine like terms: 10 + 15 = 25
3cq = 25 + 2q

Divide each side by '3q'.
c = 8.333333333q-1 + 0.6666666667

Simplifying
c = 8.333333333q-1 + 0.6666666667

Reorder the terms:
c = 0.6666666667 + 8.333333333q-1

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