3(cx-b)+c=x+d

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Solution for 3(cx-b)+c=x+d equation:


Simplifying
3(cx + -1b) + c = x + d

Reorder the terms:
3(-1b + cx) + c = x + d
(-1b * 3 + cx * 3) + c = x + d
(-3b + 3cx) + c = x + d

Reorder the terms:
-3b + c + 3cx = x + d

Reorder the terms:
-3b + c + 3cx = d + x

Solving
-3b + c + 3cx = d + x

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-1c' to each side of the equation.
-3b + c + -1c + 3cx = d + -1c + x

Combine like terms: c + -1c = 0
-3b + 0 + 3cx = d + -1c + x
-3b + 3cx = d + -1c + x

Reorder the terms:
-3b + 3cx = -1c + d + x

Add '-3cx' to each side of the equation.
-3b + 3cx + -3cx = -1c + d + -3cx + x

Combine like terms: 3cx + -3cx = 0
-3b + 0 = -1c + d + -3cx + x
-3b = -1c + d + -3cx + x

Reorder the terms:
-3b = -1c + -3cx + d + x

Divide each side by '-3'.
b = 0.3333333333c + cx + -0.3333333333d + -0.3333333333x

Simplifying
b = 0.3333333333c + cx + -0.3333333333d + -0.3333333333x

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