3(d+1)-2=8-5(d+7)

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Solution for 3(d+1)-2=8-5(d+7) equation:


Simplifying
3(d + 1) + -2 = 8 + -5(d + 7)

Reorder the terms:
3(1 + d) + -2 = 8 + -5(d + 7)
(1 * 3 + d * 3) + -2 = 8 + -5(d + 7)
(3 + 3d) + -2 = 8 + -5(d + 7)

Reorder the terms:
3 + -2 + 3d = 8 + -5(d + 7)

Combine like terms: 3 + -2 = 1
1 + 3d = 8 + -5(d + 7)

Reorder the terms:
1 + 3d = 8 + -5(7 + d)
1 + 3d = 8 + (7 * -5 + d * -5)
1 + 3d = 8 + (-35 + -5d)

Combine like terms: 8 + -35 = -27
1 + 3d = -27 + -5d

Solving
1 + 3d = -27 + -5d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '5d' to each side of the equation.
1 + 3d + 5d = -27 + -5d + 5d

Combine like terms: 3d + 5d = 8d
1 + 8d = -27 + -5d + 5d

Combine like terms: -5d + 5d = 0
1 + 8d = -27 + 0
1 + 8d = -27

Add '-1' to each side of the equation.
1 + -1 + 8d = -27 + -1

Combine like terms: 1 + -1 = 0
0 + 8d = -27 + -1
8d = -27 + -1

Combine like terms: -27 + -1 = -28
8d = -28

Divide each side by '8'.
d = -3.5

Simplifying
d = -3.5

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