3(d+1)=(3d-9)

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Solution for 3(d+1)=(3d-9) equation: 



3(d+1)=(3d-9)

We move all terms to the left:

3(d+1)-((3d-9))=0

We multiply parentheses

3d-((3d-9))+3=0



We calculate terms in parentheses: -((3d-9)), so:

(3d-9)

We get rid of parentheses

3d-9

Back to the equation:

-(3d-9)



We get rid of parentheses

3d-3d+9+3=0

We add all the numbers together, and all the variables

12!=0

There is no solution for this equation

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