3(d+1)=2(3d+9)

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Solution for 3(d+1)=2(3d+9) equation: 



3(d+1)=2(3d+9)

We move all terms to the left:

3(d+1)-(2(3d+9))=0

We multiply parentheses

3d-(2(3d+9))+3=0



We calculate terms in parentheses: -(2(3d+9)), so:

2(3d+9)

We multiply parentheses

6d+18

Back to the equation:

-(6d+18)



We get rid of parentheses

3d-6d-18+3=0

We add all the numbers together, and all the variables

-3d-15=0

We move all terms containing d to the left, all other terms to the right

-3d=15

d=15/-3

d=-5

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