3(d+1)=2d+12

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Solution for 3(d+1)=2d+12 equation: 



3(d+1)=2d+12

We move all terms to the left:

3(d+1)-(2d+12)=0

We multiply parentheses

3d-(2d+12)+3=0

We get rid of parentheses

3d-2d-12+3=0

We add all the numbers together, and all the variables

d-9=0

We move all terms containing d to the left, all other terms to the right

d=9

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