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3(d+1)=2d+12
We move all terms to the left:
3(d+1)-(2d+12)=0
We multiply parentheses
3d-(2d+12)+3=0
We get rid of parentheses
3d-2d-12+3=0
We add all the numbers together, and all the variables
d-9=0
We move all terms containing d to the left, all other terms to the right
d=9
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