3(d+1)=3(3d-9)

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Solution for 3(d+1)=3(3d-9) equation: 



3(d+1)=3(3d-9)

We move all terms to the left:

3(d+1)-(3(3d-9))=0

We multiply parentheses

3d-(3(3d-9))+3=0



We calculate terms in parentheses: -(3(3d-9)), so:

3(3d-9)

We multiply parentheses

9d-27

Back to the equation:

-(9d-27)



We get rid of parentheses

3d-9d+27+3=0

We add all the numbers together, and all the variables

-6d+30=0

We move all terms containing d to the left, all other terms to the right

-6d=-30

d=-30/-6

d=+5

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