3(d+1)=3+4(d+5)

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Solution for 3(d+1)=3+4(d+5) equation:


Simplifying
3(d + 1) = 3 + 4(d + 5)

Reorder the terms:
3(1 + d) = 3 + 4(d + 5)
(1 * 3 + d * 3) = 3 + 4(d + 5)
(3 + 3d) = 3 + 4(d + 5)

Reorder the terms:
3 + 3d = 3 + 4(5 + d)
3 + 3d = 3 + (5 * 4 + d * 4)
3 + 3d = 3 + (20 + 4d)

Combine like terms: 3 + 20 = 23
3 + 3d = 23 + 4d

Solving
3 + 3d = 23 + 4d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-4d' to each side of the equation.
3 + 3d + -4d = 23 + 4d + -4d

Combine like terms: 3d + -4d = -1d
3 + -1d = 23 + 4d + -4d

Combine like terms: 4d + -4d = 0
3 + -1d = 23 + 0
3 + -1d = 23

Add '-3' to each side of the equation.
3 + -3 + -1d = 23 + -3

Combine like terms: 3 + -3 = 0
0 + -1d = 23 + -3
-1d = 23 + -3

Combine like terms: 23 + -3 = 20
-1d = 20

Divide each side by '-1'.
d = -20

Simplifying
d = -20

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