3(d+1)=d+19

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Solution for 3(d+1)=d+19 equation: 



3(d+1)=d+19

We move all terms to the left:

3(d+1)-(d+19)=0

We multiply parentheses

3d-(d+19)+3=0

We get rid of parentheses

3d-d-19+3=0

We add all the numbers together, and all the variables

2d-16=0

We move all terms containing d to the left, all other terms to the right

2d=16

d=16/2

d=8

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