3(d+12)-d=4(d+10)

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Solution for 3(d+12)-d=4(d+10) equation: 



3(d+12)-d=4(d+10)

We move all terms to the left:

3(d+12)-d-(4(d+10))=0

We add all the numbers together, and all the variables

-1d+3(d+12)-(4(d+10))=0

We multiply parentheses

-1d+3d-(4(d+10))+36=0



We calculate terms in parentheses: -(4(d+10)), so:

4(d+10)

We multiply parentheses

4d+40

Back to the equation:

-(4d+40)



We add all the numbers together, and all the variables

2d-(4d+40)+36=0

We get rid of parentheses

2d-4d-40+36=0

We add all the numbers together, and all the variables

-2d-4=0

We move all terms containing d to the left, all other terms to the right

-2d=4

d=4/-2

d=-2

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