3(d+2)+(d-2)=

Solution for 3(d+2)+(d-2)= equation:

Simplifying
3(d + 2) + (d + -2) = 0

Reorder the terms:
3(2 + d) + (d + -2) = 0
(2 * 3 + d * 3) + (d + -2) = 0
(6 + 3d) + (d + -2) = 0

Reorder the terms:
6 + 3d + (-2 + d) = 0

Remove parenthesis around (-2 + d)
6 + 3d + -2 + d = 0

Reorder the terms:
6 + -2 + 3d + d = 0

Combine like terms: 6 + -2 = 4
4 + 3d + d = 0

Combine like terms: 3d + d = 4d
4 + 4d = 0

Solving
4 + 4d = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + 4d = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 4d = 0 + -4
4d = 0 + -4

Combine like terms: 0 + -4 = -4
4d = -4

Divide each side by '4'.
d = -1

Simplifying
d = -1