3(d+2)+1=16

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Solution for 3(d+2)+1=16 equation:


Simplifying
3(d + 2) + 1 = 16

Reorder the terms:
3(2 + d) + 1 = 16
(2 * 3 + d * 3) + 1 = 16
(6 + 3d) + 1 = 16

Reorder the terms:
6 + 1 + 3d = 16

Combine like terms: 6 + 1 = 7
7 + 3d = 16

Solving
7 + 3d = 16

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-7' to each side of the equation.
7 + -7 + 3d = 16 + -7

Combine like terms: 7 + -7 = 0
0 + 3d = 16 + -7
3d = 16 + -7

Combine like terms: 16 + -7 = 9
3d = 9

Divide each side by '3'.
d = 3

Simplifying
d = 3

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