3(d+2)+1=16-(d+1)

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Solution for 3(d+2)+1=16-(d+1) equation:


3(d+2)+1=16-(d+1)

We simplify the equation to the form, which is simple to understand 
3(d+2)+1=16-(d+1)

Reorder the terms in parentheses
+(+3d+6)+1=16-(d+1)

Remove unnecessary parentheses
+3d+6+1=+16-(+d+1+)

Remove unnecessary parentheses
+3d+6+1=16-1d-1

We move all terms containing d to the left and all other terms to the right. 
+3d+1d=+16-1-6-1

We simplify left and right side of the equation. 
+4d=+8

We divide both sides of the equation by 4 to get d. 
d=2

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