3(d+2)=4(d-1)

Solution for 3(d+2)=4(d-1) equation:

Simplifying
3(d + 2) = 4(d + -1)

Reorder the terms:
3(2 + d) = 4(d + -1)
(2 * 3 + d * 3) = 4(d + -1)
(6 + 3d) = 4(d + -1)

Reorder the terms:
6 + 3d = 4(-1 + d)
6 + 3d = (-1 * 4 + d * 4)
6 + 3d = (-4 + 4d)

Solving
6 + 3d = -4 + 4d

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '-4d' to each side of the equation.
6 + 3d + -4d = -4 + 4d + -4d

Combine like terms: 3d + -4d = -1d
6 + -1d = -4 + 4d + -4d

Combine like terms: 4d + -4d = 0
6 + -1d = -4 + 0
6 + -1d = -4

Add '-6' to each side of the equation.
6 + -6 + -1d = -4 + -6

Combine like terms: 6 + -6 = 0
0 + -1d = -4 + -6
-1d = -4 + -6

Combine like terms: -4 + -6 = -10
-1d = -10

Divide each side by '-1'.
d = 10

Simplifying
d = 10