3(d+4)-9=12(6-d)-4

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Solution for 3(d+4)-9=12(6-d)-4 equation: 



3(d+4)-9=12(6-d)-4

We move all terms to the left:

3(d+4)-9-(12(6-d)-4)=0

We add all the numbers together, and all the variables

3(d+4)-(12(-1d+6)-4)-9=0

We multiply parentheses

3d-(12(-1d+6)-4)+12-9=0



We calculate terms in parentheses: -(12(-1d+6)-4), so:

12(-1d+6)-4

We multiply parentheses

-12d+72-4

We add all the numbers together, and all the variables

-12d+68

Back to the equation:

-(-12d+68)



We add all the numbers together, and all the variables

3d-(-12d+68)+3=0

We get rid of parentheses

3d+12d-68+3=0

We add all the numbers together, and all the variables

15d-65=0

We move all terms containing d to the left, all other terms to the right

15d=65

d=65/15

d=4+1/3

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