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3(d+5)=2(d-6)
We move all terms to the left:
3(d+5)-(2(d-6))=0
We multiply parentheses
3d-(2(d-6))+15=0
We calculate terms in parentheses: -(2(d-6)), so:We get rid of parentheses
2(d-6)
We multiply parentheses
2d-12
Back to the equation:
-(2d-12)
3d-2d+12+15=0
We add all the numbers together, and all the variables
d+27=0
We move all terms containing d to the left, all other terms to the right
d=-27
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