3(d+9)+2(3d+4)=7(d+11)

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Solution for 3(d+9)+2(3d+4)=7(d+11) equation: 



3(d+9)+2(3d+4)=7(d+11)

We move all terms to the left:

3(d+9)+2(3d+4)-(7(d+11))=0

We multiply parentheses

3d+6d-(7(d+11))+27+8=0



We calculate terms in parentheses: -(7(d+11)), so:

7(d+11)

We multiply parentheses

7d+77

Back to the equation:

-(7d+77)



We add all the numbers together, and all the variables

9d-(7d+77)+35=0

We get rid of parentheses

9d-7d-77+35=0

We add all the numbers together, and all the variables

2d-42=0

We move all terms containing d to the left, all other terms to the right

2d=42

d=42/2

d=21

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