3(d-1)-(2d-4)=1

Solution for 3(d-1)-(2d-4)=1 equation:

Simplifying
3(d + -1) + -1(2d + -4) = 1

Reorder the terms:
3(-1 + d) + -1(2d + -4) = 1
(-1 * 3 + d * 3) + -1(2d + -4) = 1
(-3 + 3d) + -1(2d + -4) = 1

Reorder the terms:
-3 + 3d + -1(-4 + 2d) = 1
-3 + 3d + (-4 * -1 + 2d * -1) = 1
-3 + 3d + (4 + -2d) = 1

Reorder the terms:
-3 + 4 + 3d + -2d = 1

Combine like terms: -3 + 4 = 1
1 + 3d + -2d = 1

Combine like terms: 3d + -2d = 1d
1 + 1d = 1

Add '-1' to each side of the equation.
1 + -1 + 1d = 1 + -1

Combine like terms: 1 + -1 = 0
0 + 1d = 1 + -1
1d = 1 + -1

Combine like terms: 1 + -1 = 0
1d = 0

Solving
1d = 0

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Divide each side by '1'.
d = 0

Simplifying
d = 0