3(d-10)+2(d-22)=6

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Solution for 3(d-10)+2(d-22)=6 equation:


Simplifying
3(d + -10) + 2(d + -22) = 6

Reorder the terms:
3(-10 + d) + 2(d + -22) = 6
(-10 * 3 + d * 3) + 2(d + -22) = 6
(-30 + 3d) + 2(d + -22) = 6

Reorder the terms:
-30 + 3d + 2(-22 + d) = 6
-30 + 3d + (-22 * 2 + d * 2) = 6
-30 + 3d + (-44 + 2d) = 6

Reorder the terms:
-30 + -44 + 3d + 2d = 6

Combine like terms: -30 + -44 = -74
-74 + 3d + 2d = 6

Combine like terms: 3d + 2d = 5d
-74 + 5d = 6

Solving
-74 + 5d = 6

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '74' to each side of the equation.
-74 + 74 + 5d = 6 + 74

Combine like terms: -74 + 74 = 0
0 + 5d = 6 + 74
5d = 6 + 74

Combine like terms: 6 + 74 = 80
5d = 80

Divide each side by '5'.
d = 16

Simplifying
d = 16

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