3(d-10)+4(d-18)=10

Solution for 3(d-10)+4(d-18)=10 equation:

Simplifying
3(d + -10) + 4(d + -18) = 10

Reorder the terms:
3(-10 + d) + 4(d + -18) = 10
(-10 * 3 + d * 3) + 4(d + -18) = 10
(-30 + 3d) + 4(d + -18) = 10

Reorder the terms:
-30 + 3d + 4(-18 + d) = 10
-30 + 3d + (-18 * 4 + d * 4) = 10
-30 + 3d + (-72 + 4d) = 10

Reorder the terms:
-30 + -72 + 3d + 4d = 10

Combine like terms: -30 + -72 = -102
-102 + 3d + 4d = 10

Combine like terms: 3d + 4d = 7d
-102 + 7d = 10

Solving
-102 + 7d = 10

Solving for variable 'd'.

Move all terms containing d to the left, all other terms to the right.

Add '102' to each side of the equation.
-102 + 102 + 7d = 10 + 102

Combine like terms: -102 + 102 = 0
0 + 7d = 10 + 102
7d = 10 + 102

Combine like terms: 10 + 102 = 112
7d = 112

Divide each side by '7'.
d = 16

Simplifying
d = 16