3(d-2)-10=3(2-d)+8

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Solution for 3(d-2)-10=3(2-d)+8 equation: 



3(d-2)-10=3(2-d)+8

We move all terms to the left:

3(d-2)-10-(3(2-d)+8)=0

We add all the numbers together, and all the variables

3(d-2)-(3(-1d+2)+8)-10=0

We multiply parentheses

3d-(3(-1d+2)+8)-6-10=0



We calculate terms in parentheses: -(3(-1d+2)+8), so:

3(-1d+2)+8

We multiply parentheses

-3d+6+8

We add all the numbers together, and all the variables

-3d+14

Back to the equation:

-(-3d+14)



We add all the numbers together, and all the variables

3d-(-3d+14)-16=0

We get rid of parentheses

3d+3d-14-16=0

We add all the numbers together, and all the variables

6d-30=0

We move all terms containing d to the left, all other terms to the right

6d=30

d=30/6

d=5

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