3(d-2)=2(4d+7)

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Solution for 3(d-2)=2(4d+7) equation: 



3(d-2)=2(4d+7)

We move all terms to the left:

3(d-2)-(2(4d+7))=0

We multiply parentheses

3d-(2(4d+7))-6=0



We calculate terms in parentheses: -(2(4d+7)), so:

2(4d+7)

We multiply parentheses

8d+14

Back to the equation:

-(8d+14)



We get rid of parentheses

3d-8d-14-6=0

We add all the numbers together, and all the variables

-5d-20=0

We move all terms containing d to the left, all other terms to the right

-5d=20

d=20/-5

d=-4

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