3(d-3)=4(2d-1)

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Solution for 3(d-3)=4(2d-1) equation: 



3(d-3)=4(2d-1)

We move all terms to the left:

3(d-3)-(4(2d-1))=0

We multiply parentheses

3d-(4(2d-1))-9=0



We calculate terms in parentheses: -(4(2d-1)), so:

4(2d-1)

We multiply parentheses

8d-4

Back to the equation:

-(8d-4)



We get rid of parentheses

3d-8d+4-9=0

We add all the numbers together, and all the variables

-5d-5=0

We move all terms containing d to the left, all other terms to the right

-5d=5

d=5/-5

d=-1

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