3(d-4)+2-2d+1-d=(-9)-2d

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Solution for 3(d-4)+2-2d+1-d=(-9)-2d equation:



3(d-4)+2-2d+1-d=(-9)-2d
We move all terms to the left:
3(d-4)+2-2d+1-d-((-9)-2d)=0
We add all the numbers together, and all the variables
-3d+3(d-4)-((-9)-2d)+3=0
We multiply parentheses
-3d+3d-((-9)-2d)-12+3=0
We calculate terms in parentheses: -((-9)-2d), so:
(-9)-2d
determiningTheFunctionDomain -2d+(-9)
We add all the numbers together, and all the variables
-2d-9
Back to the equation:
-(-2d-9)
We add all the numbers together, and all the variables
-(-2d-9)-9=0
We get rid of parentheses
2d+9-9=0
We add all the numbers together, and all the variables
2d=0
d=0/2
d=0

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