3(d-4)=2(6-3d)

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Solution for 3(d-4)=2(6-3d) equation: 



3(d-4)=2(6-3d)

We move all terms to the left:

3(d-4)-(2(6-3d))=0

We add all the numbers together, and all the variables

3(d-4)-(2(-3d+6))=0

We multiply parentheses

3d-(2(-3d+6))-12=0



We calculate terms in parentheses: -(2(-3d+6)), so:

2(-3d+6)

We multiply parentheses

-6d+12

Back to the equation:

-(-6d+12)



We get rid of parentheses

3d+6d-12-12=0

We add all the numbers together, and all the variables

9d-24=0

We move all terms containing d to the left, all other terms to the right

9d=24

d=24/9

d=2+2/3

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