3(d-4)=4(d+2)

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Solution for 3(d-4)=4(d+2) equation: 



3(d-4)=4(d+2)

We move all terms to the left:

3(d-4)-(4(d+2))=0

We multiply parentheses

3d-(4(d+2))-12=0



We calculate terms in parentheses: -(4(d+2)), so:

4(d+2)

We multiply parentheses

4d+8

Back to the equation:

-(4d+8)



We get rid of parentheses

3d-4d-8-12=0

We add all the numbers together, and all the variables

-1d-20=0

We move all terms containing d to the left, all other terms to the right

-d=20

d=20/-1

d=-20

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