3(d-5)=2(d+6)

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Solution for 3(d-5)=2(d+6) equation: 



3(d-5)=2(d+6)

We move all terms to the left:

3(d-5)-(2(d+6))=0

We multiply parentheses

3d-(2(d+6))-15=0



We calculate terms in parentheses: -(2(d+6)), so:

2(d+6)

We multiply parentheses

2d+12

Back to the equation:

-(2d+12)



We get rid of parentheses

3d-2d-12-15=0

We add all the numbers together, and all the variables

d-27=0

We move all terms containing d to the left, all other terms to the right

d=27

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