3(d-5)=21

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Solution for 3(d-5)=21 equation: 



3(d-5)=21

We move all terms to the left:

3(d-5)-(21)=0

We multiply parentheses

3d-15-21=0

We add all the numbers together, and all the variables

3d-36=0

We move all terms containing d to the left, all other terms to the right

3d=36

d=36/3

d=12

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